What numbers are divisible by 9 from 1 to 200?
The numbers which satisfy the given condition are 9, 18, 36, 45, 63, 72. 90, 99, 117, 126.
Hence, a total of 22 numbers are divisible by 9 between 1 and 200.
Solution: (i) Integers between 100 and 200, that are divisible by 9 are 108,117,126,…,198.
List of Numbers Divisible by 9. There are 11 numbers less than 100 that are divisible by 9: 9, 18, 27, 36, 45, 63, 72, 81, 90 and 99.
For example, 18 is 1+8 = 9, which is divisible by 9, 27 is 2+7 = 9, which is divisible by 9, etc. So, as per the divisibility test of 9, if the sum of all the digits of a number is a multiple of 9, then the number is also divisible by 9.
Answer and Explanation:
200 divided by 9 is 22.22222... or 22 2/9. If we plug 200 divided by 9 into a calculator, the result will be 22.2222..., where the 2s go on forever....
Between 1 and 200 (including 1 and 200), there are 492 digits.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, 180, 189, 198, 207, 216, 225, 234, 243, 252, 261, 270, 279, 288, 297, 306, 315, 324, 333, 342, 351, 360, 369, 378, 387, 396, 405, 414, 423, 432, 441, 450, 459, 468, 477, 486, 495, 504, 513, 522, 531, 540, 549, 558, 567, 576, 585, 594, ...
∴ Only two number can divisible by 6, 8 and 9 between 200 and 300.
135 and 180 are the numbers between 100 and 200 that are exactly divisible by both 9 and 15.
Which number is divisible by all 1 to 9?
That number is 2520, and there is no number smaller that is divisible by all the integers 1 - 9. Below is a breakdown: 2520 divided by 2520 equals 1.
There are total 20 nines between 1–100.
Answer: There are 111 numbers between 1 and 1000 divisible by 9.
33 numbers are between 1 and 300, which are divisible by 9.
The factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100 and 200.
Factors of 200: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100 and 200.
There's an easy and fun way to tell if a number is divisible by 9! Simply add all the digits of the number and then divide by 9. If the digits add to a multiple of 9, then the number is divisible by 9!
| Range of Numbers | List of Prime Numbers | Total |
|---|---|---|
| 1 to 100 | 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 | 25 |
| 101 - 200 | 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199 | 21 |
1, 3, 7, 9, 13, 15, 21, 25, 31, 33, 37, 43, 49, 51, 63, 67, 69, 73, 75, 79, 87, 93, 99, 105, 111, 115, 127, 129, 133, 135, 141, 151, 159, 163, 169, 171, 189, 193, 195, 201, 205, 211, 219, 223, 231, 235, 237, 241, 259, 261, 267, 273, 283, 285, 289, 297, 303, 307, 319, 321, 327, ... (sequence A000959 in the OEIS).
9 is at the tens place, which represents 9 tens or 90.
What are the 9 multiples of 200?
Multiples of 200: 200, 400, 600, 800, 1000, 1200, 1400, 1600, 1800, 2000 and so on.
We have to find the sum of the series. The integers between 100 and 200 are 101, 102, 103,......,199. Therefore, the series is 108, 117, 126,......., 198. Therefore, the sum of the integers between 100 and 200 that are not divisible by 9 is 13167.
The multiple of 9 below 200 are : 9,18,27,36,45,54,63,72,81,90,99,108,117,126,135,144,153,162,171,180,189,198.
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The numbers lying between 200 and 400, which are divisible by 9 are, 207, 216, 225, .... 396. Let the number of terms of the A.P. be n. Thus, the required sum is 6633.
Correct Option: B. A number is divisible by 9 and 6 both, if it is divisible by LCM of 9 and 6 i.e., 18. Hence, the numbers are 108, 126, 144, 162, 180, 198.
1 Answer. The integers between 101 and 500 divisible by 9 are 108, 117, 126,…, 495(Add 9 to 108 to get 117, 9 to 117 to get 126 and so on). Sum of all integers divisible by 9 between 100 and 500 is 13266.
Hence, required sum of the integers between 100 and 200 that are divisible by 9 is 1693.
Hence, the common multiples of 9 and 15 are 45, 90, 135…. Note: The other way of solving the above problem is to write the multiples of 9 and 15 separately and then find the common multiples among 5 and 19. From the above, you can see that 45 and 135 are the common multiples.
The sum of all integers between 200 and 800, which is divisible by 9 is "(d) 32967". The above sreies are in AP. Hence, the sum of all integers between 200 and 800, which is divisible by 9 is "(d) 32967".
Note: Zero is divisible by any number (except by itself), so gets a "yes" to all these tests.
Is 15 is divisible by 9?
15 divided by 9 = 1.
The result of 15/9 is a non-terminating, repeating decimal.
Numbers that are divisible by 8 are 8, 16, 24, etc. Numbers that are divisible by 9 are 9, 18, 27, etc.
Answer. Total cards =100 The numbers those are divisible by 9 and are perfect squares are 9, 36, 81.
In mathematics
2520 is: the smallest number divisible by all integers from 1 to 10, i.e., it is their least common multiple. half of 7! (5040), meaning 7 factorial, or 1×2×3×4×5×6×7.
Answer: 9, 18, 27, 36, 45.
UPSC Mains
Q. How many numbers are between 100 to 200? Notes: This question is very easy, here we can get the numbers between 100 to 200 just by this simple calculation, (200-100) + 1 = 101.
101 , 111 , 121 , 131 , 141 , 151 , 161 , 171 , 181 , 191.
There are total 20 nine's between 1 and 100. 9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99.
So the there are total 1000 terms between 1000 and 9999 which are divisible by 9.
Solutions. The first ten multiples of 9 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90.
How many numbers are divisible by 8 from 1 to 200?
So, there are 25 numbers divisible by 8 from 1 to 200.
There are 15 integers between 1 and 200 that can be divided by either 2 or 9.
The largest 3 digit number is 999, we can see that 999 is divisible by 9 because it satisfies the divisibility rule for 9. The sum of digits of 999 is 27 and 27 is divisible by 9.
Ans. The number of all multiples of 9 lying between 300 and 700 is 44.
- 9 divided by 100 in decimal = 0.09.
- 9 divided by 100 in fraction = 9/100.
- 9 divided by 100 in percentage = 9%
36 divided by 9 is 4.
There are total 20 nines between 1–100.
20 numbers are divisible by 10 from 1 to 200 !
We have to find the sum of the series. The integers between 100 and 200 are 101, 102, 103,......,199. Therefore, the series is 108, 117, 126,......., 198. Therefore, the sum of the integers between 100 and 200 that are not divisible by 9 is 13167.
Total 11 numbers are there which are divisible by 9 ranges between 1 to 100.
How many is 9 in 100?
There is a total of 20 nines between 1-100.
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The numbers lying between 200 and 400, which are divisible by 9 are, 207, 216, 225, .... 396. Let the number of terms of the A.P. be n. Thus, the required sum is 6633.
So, there are 25 numbers divisible by 8 from 1 to 200.
Avis wrote: What is the total number of integers between 100 and 200 that are divisible by 3? (198 - 102)/3 + 1 = 33.
So, there are 20 numbers divisible by 5 in the range 101 to 200. Therefore, this is the required result in the given question.
So, the sum of integers between 100 and 200 which are not divisible by 9 = 14850 – 1683 = 13167.
The required sum =S−s=15050−3050=12000.